|
|
Section P.3 Operations with Polynomials We will cover: Subtraction Multiplication We will not cover Addition of polynomials or combining like terms. You should know this material from previous algebra courses. Please see page 29, Example 2 part a.
Subtraction Drop the parentheses and distribute the subtraction sign to all of the terms after the subtraction sign. Do these steps at the same time. Note: All terms following the subtraction sign will change to the opposite sign. See next slide for an Example.
Example of Polynomial Subtraction 7 π₯ 4 β π₯ 2 β4π₯+2 β(3 π₯ 4 β4 π₯ 2 +3π₯) 7 π₯ 4 β π₯ 2 β4π₯+2β3 π₯ 4 +4 π₯ 2 β3π₯ (signs in red are now opposite because the subtraction sign has been distributed) Next, reorder terms so that like terms are together 7 π₯ 4 β3 π₯ 4 β π₯ 2 +4 π₯ 2 β4π₯β3π₯+2 Final Answer: 4 π₯ 4 +3 π₯ 2 β7π₯+2
Another Example of Subtraction β 5 π₯ 2 β1 β β3 π₯ 2 +5 We now have two subtraction signs to distribute: β5 π₯ 2 +1+3 π₯ 2 β5 Letβs reorder the terms: β5 π₯ 2 +3 π₯ 2 +1β5 Final Answer: β2 π₯ 2 β4
A 3rd Example of Subtraction π¦ 3 +1 β[ π¦ 2 +1 + 3π¦β7 ] Letβs add the two polynomials in the brackets first (result shown in blue): π¦ 3 +1 β π¦ 2 +3π¦β6 Next, drop the parentheses and distribute the subtraction sign: π¦ 3 +1β π¦ 2 β3π¦+6 Letβs reorder the terms: π¦ 3 β π¦ 2 β3π¦+1+6 Final Answer: π¦ 3 β π¦ 2 β3π¦+7
A 4th Example of Subtraction 3 π₯ 3 β2 π₯ 2 β5π₯+2 β4( π₯ 3 + π₯ 2 β4π₯) Distribute the 3 and the 4 first. Then, drop parentheses and distribute the subtraction sign. 3 π₯ 3 β6 π₯ 2 β15π₯+6 β(4 π₯ 3 +4 π₯ 2 β16π₯) 3 π₯ 3 β6 π₯ 2 β15π₯+6β4 π₯ 3 β4 π₯ 2 +16π₯ Reorder terms so that like terms are together: 3 π₯ 3 β4 π₯ 3 β6 π₯ 2 β4 π₯ 2 β15π₯+16π₯+6 Final Answer: β π₯ 3 β10 π₯ 2 +π₯+6
Multiplication: Distributing a monomial Example: π¦ 2 4 π¦ 2 +2π¦β3 Multiply the π¦ 2 times each term in the parentheses. Iβve highlighted in red the signs that are carried over from the original problem. (π¦ 2 ) 4 π¦ 2 + (π¦ 2 ) 2π¦ β (π¦ 2 )(3) Final Answer: 4 π¦ 4 +2 π¦ 3 β3 π¦ 2
Another Example of Distributing a Monomial β3π₯ π₯ 2 β2π₯+1 Multiply β3π₯ times each term inside the parentheses. Iβve highlighted in red the signs that are carried over from the original problem. β3π₯ π₯ 2 β β3π₯ 2π₯ +(β3π₯)(1) β3 π₯ 3 β β6 π₯ 2 + β3π₯ Final Answer: β3 π₯ 3 +6 π₯ 2 β3π₯
Multiplying a binomial times a binomial: The FOIL method Multiply using FOIL: (2π₯β4)(π₯+5) First terms + Outer terms + Inner terms + Last terms 2π₯ π₯ + 2π₯ 5 + β4 π₯ +(β4)(5) 2 π₯ 2 +10π₯+ β4π₯ + β20 2 π₯ 2 +10π₯β4π₯β20 Final Answer: 2 π₯ 2 +6π₯β20
Another Example of FOIL 7π₯β2 4π₯β3 First terms + Outer terms + Inner terms + Last terms 7π₯ 4π₯ + 7π₯ β3 + β2 4π₯ +(β2)(β3) 28 π₯ 2 + β21π₯ + β8π₯ +6 28 π₯ 2 β21π₯β8π₯+6 Final Answer: 28 π₯ 2 β29π₯+6
Multiplying the sum and difference of the same terms General Rule: π+π πβπ = π 2 β π 2 Example: π₯+5 π₯β5 FOIL: π₯ π₯ + π₯ β5 + 5 π₯ +5 β5 π₯ 2 β5π₯+5π₯β25 (middle terms cancel out) Final Answer: π₯ 2 β25 Note: π₯ 2 β25= π₯ 2 β 5 2 (Recall the General Rule: π 2 β π 2 )
Another Example 5π₯β9 5π₯+9 FOIL: 5π₯ 5π₯ + 5π₯ 9 + β9 5π₯ +(β9)(9) 25 π₯ 2 +45π₯β45π₯β81 Final Answer: 25 π₯ 2 β81 Note: 25 π₯ 2 β81= 5π₯ 2 β 9 2 (Recall the General Rule: π 2 β π 2 )
The Square of a Binomial Every time you square a two term expression, such as π+π 2 or aβb 2 , be sure to avoid these common mistakes shown below. Examples of common mistakes: π₯+2 2 = π₯ 2 + 2 2 = π₯ 2 +4 FALSE 2π₯β3 2 = 2π₯ 2 β 3 2 =4 π₯ 2 β9 FALSE
Squaring a Binomial is in Fact a FOIL problem: You should always have a middle term when squaring a binomial Examples: π₯+3 2 = π₯+3 π₯+3 = π₯ 2 +3π₯+3π₯+9 = π₯ 2 +6π₯+9 3π₯β4 2 = 3π₯β4 3π₯β4 =9 π₯ 2 β12π₯β12π₯+16 =9 π₯ 2 β24π₯+16 Note: The last term is ALWAYS positive when you square a binomial. (see signs highlighted in blue)
Shortcut Formulas for squaring a binomial 1st Formula: π+π 2 = π 2 +2ππ+ π 2 Example: 2π₯+1 2 = 2π₯ 2 +2 2π₯ 1 + 1 2 =4 π₯ 2 +4π₯+1 In previous example, π=2π₯ and π=1. 2nd Formula: πβπ 2 = π 2 β2ππ+ π 2 Example: 4π₯β5 2 = 4π₯ 2 β2 4π₯ 5 + 5 2 =16 π₯ 2 β40π₯+25 In previous example, π=4π₯ and π=5.
Multiplying polynomials where each polynomial has two or more terms Example: (π₯+2)( π₯ 2 β3π₯+4) We will use a technique of setting up a table to perform the multiplication. The first polynomialβs terms are arranged vertically on the left side while the three terms of the second polynomial are arranged along the top of the table. I will insert the signs in the table as well. The terms in each row and column will be multiplied and the result is placed in the appropriate box in red. Note that like terms are arranged diagonally. Answer: π₯ 3 +2 π₯ 2 β3 π₯ 2 β6π₯+4π₯+8= π₯ 3 β π₯ 2 β2π₯+8
Another Example of Table Multiplication Multiply: β π₯ 2 +π₯β5 3 π₯ 2 +4π₯+1 Answer: β3 π₯ 4 +3 π₯ 3 β4 π₯ 3 β15 π₯ 2 +4 π₯ 2 β π₯ 2 β20π₯+π₯β5= β3 π₯ 4 β π₯ 3 β12 π₯ 2 β19π₯β5
Cubing a binomial Example of cubing a binomial: 2π₯+1 3 Common Mistake to Avoid: 2π₯+1 3 = 2π₯ 3 + 1 3 =8 π₯ 3 +1 FALSE Correct Way: 2π₯+1 3 = 2π₯+1 2π₯+1 2π₯+1 FOIL the first two: (4 π₯ 2 +4π₯+1)(2π₯+1) Finish by using table multiplication. Answer: 8 π₯ 3 +12 π₯ 2 +6π₯+1
Summary: This covers most of Section P3 out of Ron Larson's College Algebra textbook.
| URL: |
No comments posted yet
Comments